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The points and path in Figure 4 should be understood. Note that for clarity, the circle Re=0.25 and theĬurve Im=-1.732 is shown. Impedance matching process is shown in Figure 4. The impedance z1 can then be easily matched with a series inductor with a reactance of zL = i*1.7321. Hence, the parallelĬapacitor required will have a susceptance of 圜 = y1-y_A = i*0.683, or zC = -i*1.464. The intersection of the Re=0.25 and the Re=1 circles occursĪt location z1, given by z1 = 1 - i*1.7321. The goal is to intersect the Re=1 constant resistance circle so that With a parallel capacitor, we will move along the Note that z_A can be rewritten as y_A = 0.25 - i*0.25. Inductor to move the impedance to intersect the Re=1 circle. In fact, we have two options here: we can use a parallel capacitor or a parallel Which is no big deal, since we can simply use a parallel component to move the impedance to intersect the Re=1Ĭircle.

Impedance to intersect the Re=1 or the Re=1 circles, we find we can't do it. However, if we try to use a series component to move the In the previous example we did matching with a seriesĬomponent followed by a parallel component. Let's take a look at the impedance z_A = 2 + i*2. Page this was done with a series inductor and a parallel capacitor. Hence, we have performed impedance matching using a series capacitor and a parallel inductor on the previous The impedance matching network for Example 1. This impedance matching network is shown in Figure 3:įigure 3. A parallel inductor cancels out the susceptance. That is, if we addĪ parallel inductor with a susceptance of -i*3, the impedance will be translated to the center of theįigure 2. To complete the impedance matching, we just need to cancel out the susceptance. Using a Series Capacitor to Move zA to the Re=1 circle. This is illustrated in Figure 1:įigure 1.

Will be transformed to z1=0.1-i*0.3, which is equivalent to y1=1+i*3.

Using a capacitor with a series reactance of -i*0.1, the impedance By observing the immittance Smith Chart, we could also accomplish this withĪ series capacitor.

Recall that we moved the impedance z_A to intersect the Re=1 circle with a series What alternatives do we have to match this impedance? Matched an antenna with impedance z_A=0.1-i*0.2 with a series inductor and a parallelĬapacitor. In Example 1 on the immittance Smith Chart page, we Impedance matching examples to illustrate the usefulness of the immittance Smith Chart. On the previous page, the immittance Smith Chart was introduced. Include Form Remove Scripts Accept Cookies Show Images Show Referer Rotate13 Base64 Strip Meta Strip Title Session Cookies Immittance Charts: More Impedance Matching Previous: Immittance Smith Chart